第1章 矩阵运算与矩阵分解_3(18)

矩阵论与数值分析

1 from which we obtain an eigenvector 1 1 of 1 1. 0 0 Similarly, for 2 1, we have an eigenvector 2 1 . 2 for 3 3, we have an eigenvector 3 3 . 1

1

1 Let P 1

0 1

2 3 , then P 1 AP diag{1, 1,3}.