96819部队指挥楼工程 施工组织设计
Kx = 0.60，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.60× 16.00 = 9.60kW 5) 钢筋切断机组
Kx = 0.60，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.60× 11.00 = 6.60kW 6) 直螺纹机组
Kx = 0.60，Cosφ = 0.75，tgφ =0 .88 Pjs = Kx×Pe = 0.60× 16.00 = 9.60kW 7) 无齿锯组
Kx = 0.60，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.60× 9.00 = 5.40kW 8) 电焊机组
Kx = 0.70，Cosφ = 0.90，tgφ =0 .48 Pjs = Kx×Pe = 0.70× 15.00 = 10.50kW 9) 电刨子组
Kx = 0.60，Cosφ = 0.75，tgφ =0 .88 Pjs = Kx×Pe = 0.60× 4.00 = 2.40kW 10) 压刨组
Kx = 0.60，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.60× 5.50 = 3.30kW
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96819部队指挥楼工程 施工组织设计
11) 圆盘锯组
Kx = 0.60，Cosφ = 0.75，tgφ =0 .88 Pjs = Kx×Pe = 0.60× 8.00 = 4.80kW
12) 第一路电源总的负荷计算，干线同期系数取 Kx = 0.90 总的有功功率
Pjs=Kx×ΣPjs=0.90×(30.00+36.00+9.60+9.60+6.60+9.60+5.40+10.50+2.40+3.30+4.80) = 115.02kW 总的无功功率
Qjs=Kx×ΣQjs=0.90×(26.4+31.68+8.45+9.6+5.8+8.45+4.75+5.04+2.11+2.90+4.22) = 98.46kVA 总的视在功率
Sjs = (Pjs2+Qjs2)1/2 = (115.022+98.462)1/2 = 151.40kVA 总的计算电流计算
Ijs = Sjs/(1.732×Ue) = 151.40/(1.732×0.38) = 229.39A (2)确定第二路电源用电负荷 1) 塔吊组
Kx = 0.50，Cosφ = 0.75，tgφ =0 .88 Pjs = Kx×Pe = 0.50× 60.00 = 30.00Kw 2) 电焊机组
Kx = 0.70，Cosφ = 0.90，tgφ =0 .48
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96819部队指挥楼工程 施工组织设计
Pjs = Kx×Pe = 0.70× 45.00 = 31.50kW 3) 振捣棒组
Kx = 0.60，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.60× 6 = 3.60kW 4) 低压变压器组
Kx = 0.90，Cosφ = 0.90，tgφ =0 .48 Pjs = Kx×Pe = 0.90× 12.00 = 10.80kW 5) 蛙式夯机组
Kx = 0.70，Cosφ = 0.75，tgφ = 0.88 Pjs = Kx×Pe = 0.70×8.80 = 6.16kW 6) 现场镝灯组
Kx = 0.60，Cosφ = 0.99，tgφ = 0.14 Pjs = Kx×Pe = 0.60× 28.00 = 16.80kW 7) 蒸饭车组
Kx = 0.40，Cosφ = 0.90，tgφ = 0.48 Pjs = Kx×Pe = 0.40× 36.00 = 14.40kW 8) 电开水器组
Kx = 0.60，Cosφ = 0.90，tgφ = 0.48 Pjs = Kx×Pe = 0.60× 18.00 = 10.80kW
42) 第二路电源总的负荷计算，干线同期系数取 Kx = 0.90
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96819部队指挥楼工程 施工组织设计
总的有功功率
Pjs=Kx×ΣPjs=0.90×(30.00+31.50+3.60+10.80+6.16+16.80+14.40+10.80) = 111.65kW 总的无功功率
Qjs=Kx×ΣQjs=0.90×(26.40+15.12+3.17+5.18+5.42+2.35+6.91+5.18) = 62.75kVA 总的视在功率
Sjs = (Pjs2+Qjs2)1/2 = (111.652+62.752)1/2 = 128.08kVA 总的计算电流计算
Ijs = Sjs/(1.732×Ue) = 128.03/(1.732×0.38) = 193.98A (3)确定第三路电源用电负荷 1) 空调组
Kx = 0.60，Cosφ = 0.90，tgφ = 0.48 Pjs = Kx×Pe = 0.60× 27 = 16.20kW 2) 照明组
Kx = 0.50，Cosφ = 0.78，tgφ = 0.8 Pjs = Kx×Pe = 0.50× 2.16 = 1.08kW 3) 电脑组
Kx = 0.50，Cosφ = 0.78，tgφ =0 .8 Pjs = Kx×Pe = 0.50× 33.6 = 16.80kW
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96819部队指挥楼工程 施工组织设计
4) 第三路电源总的负荷计算，干线同期系数取 Kx = 0.90 总的有功功率
Pjs = Kx×ΣPjs = 0.90×(16.20+1.08+16.80) = 30.67kW 总的无功功率
Qjs = Kx×ΣQjs = 0.90×(7.78+0.86+13.44) =19.87VA 总的视在功率
Sjs = (Pjs2+Qjs2)1/2 = (30.672+19.872)1/2 = 36.54kVA 总的计算电流计算
Ijs = Sjs/(1.732×Ue) = 36.54/(1.732×0.38) = 55.36A 4.2.3开关容量选择
根据计算的总的视在功率及计算总的电流容量，第一路电源选用甲方提供的400A断路器开关，第二路电源选用甲方提供的400A断路器开关，第三路电源选用甲方提供的100A断路器开关。 4.3、现场临时用水设计 4.3.1、临时用水计划
施工现场生产及生活临时设施给水计划。 4.3.2、水源
生活用水接自现场南侧给水阀门井，并安装阀门、水表。生活用水接DN40的热镀锌钢管，供现场施工人员日常使用，以保证水质。 4.3.3、总用水量计算
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