概率论与数理统计第二版考点习题答案(2)

2019-01-27 10:44

答案仅供参考

P(X?2)?1?0.6?0.1?0.3

所以X的分布律为

X P X的分布函数为

1

2 0.3 3 0.1 0.6 x?1?0?0.61?x?2? F(x)??0.92?x?3???1x?3 2.20(1)

P{Y?0}?P{X?}?0.22P{Y??2}?P{X?0}?P{X??}?0.3?0.4?0.7

3?P{Y?4?2}?P{X?}?0.12? Y

0 0.2

?2 0.7

4?2 0.1

qi (2)

P{Y??1}?P{X?0}?P{X??}?0.3?0.4?0.7 ?3?P{Y?1}?P{X?}?P{X?}?0.2?0.1?0.322Y -1 0.7

1 0.3

qi

答案仅供参考

2.21(1)

当?1?x?1时,F(x)?P{X??1}?0.3

当1?x?2时,F(x)?P{X??1}?P{X?1}?0.3?P{X?1}?0.8

P{X?1}?0.8?0.3?0.5

当x?2时,F(x)?P{X??1}?P{X?1}?P{X?2}?0.8?P{X?2}?1

P{X?2}?1?0.8?0.2

X P (2)

-1 0.3

1 0.5

2 0.2

P{Y?1}?P{X??1}?P{X?1}?0.3?0.5?0.8 P{Y?2}?P{X?2}?0.2

Y 1 0.8

2 0.2

qi

2.22

1?x2X~N(0,1)?fX(x)?e

2?2(1)设FY(y),fY(y)分别为随机变量Y的分布函数和概率密度函数,则

FY(y)?P{Y?y}?P{2X?1?y}?P{X?y?1}??2y?12??1e2??x22dx

答案仅供参考

y?12)?22(21对FY(y)求关于y的导数,得fY(y)?e2?y?(??,?)

(y?1)?y?11()??e8 222?(2)设FY(y),fY(y)分别为随机变量Y的分布函数和概率密度函数,则 当y?0时,FY(y)?P{Y?y}?P{e?X?y}?P{?}?0 当y?0时,有

x22FY(y)?P{Y?y}?P{e?X?y}?P{?X?lny}?P{X??lny}??对FY(y)求关于y的导数,得

(lny)?1?(?lny)y>0?122??e(?lny)?e?fY(y)??2?2?y ?y?0?022??lny1e2??dx

(3)设FY(y),fY(y)分别为随机变量Y的分布函数和概率密度函数,则 当y?0时,FY(y)?P{Y?y}?P{X2?y}?P{?}?0

当y>0时,FY(y)?P{Y?y}?P{X2?y}?P{?y?X?y}??对FY(y)求关于y的导数,得

y?y1?x2edx 2?2?1?(e?fY(y)??2???0y)221?(y)??e2?(?y)22(lny)?1(?y)??e2 2?y2y>0y?0

答案仅供参考

2.23 ∵X0?x???1?U(0,?)∴fX(x)???

?其它?0(1)

当2ln??y??时

FY(y)?P{Y?y}?P{2lnX?y}?P{lnX2?y}?P{?}?0 当???y?2ln?时yFY(y)?P{Y?y}?P{2lnX?y}?P{lnX2?y}?P{X2?ey}?P{X?ey}??e210?dx

yy???y2?l?n?1212e?(e)??对FY(y)求关于y的导数,得到fY(y)??? 2?

?02l?n?y???(2)

当y?1或 y?-1时,FY(y)?P{Y?y}?P{cosX?y}?P{?}?0

当?1?y?1时,FY(y)?P{Y?y}?P{cosX?y}?P{X?arccosy}??对FY(y)求关于y的导数,得到

1?1?1?y?1??(arccosy)??fY(y)??? ?1?y2

?0其它??1arccosy?dx

(3)当y?1或 y?0时FY(y)?P{Y?y}?P{sinX?y}?P{?}?0

当0?y?1时,

答案仅供参考

FY(y)?P{Y?y}?P{sinX?y}?P{0?X?arcsiny}?P{??arcsiny?X??}??arcsiny10?dx???1??arcsiny?dx

对FY(y)求关于y的导数,得到

12?10?y?1??arcsiny?(??arcsiny)???fY(y)??? ?1?y2

?0其它?

习题3参考答案

3.1 P{1

Y X 2 0 1 2 3 128ccc345222=3 53 ccc3453122= 50 13.4(1)a=

9(2)

5 12


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