线性代数第五版答案(全)(4)

41(1)0解

1251202112542;072024c2 c342======10 1

23202 104 1 10

2=122×( 1)4+3 14410

1

1

7c4

7c3001

3 14=4 110c2+c399123 142======c0010 2=0.1+2c31714

241(2)31 1252103162;22 1

404解

3121211c4 c2r5

36

2=====223 1142152200

==4 r3==22=3

12006

22

21132400

r4 r12

140=====312122030

0=0.00

(3) bdabbf acaecfcd deef

;

解

bdabbf accfcdae deef=adf bbceb cc ee=adfbce 1111 111

1=4abcdef.