好东西
231
(3) A= 131 ,
122
s 2
sI A= 1
1
3s 3 2
1
1=s3 7s2+10s 4, s 2
s2 5s+4 3s 4s
1 12
(sI A)=3s 4s+3s 1 . s 12
s 7s+10s 4 2
+s12s1s5s3
10 0 0
7．解：(1) A= 2 30 ，B= 1 ， C=(001).
113 2
110 0
(2) A= 001 , B= 0
1 3 1 2
khd
2s2+7s+3
.=3
s 7s 6
课
0 s2 90s 3
12
(001) 2s+6s 3s0=3 1
s 7s 6 2 . s 52
132 ++sss
答
0 s 1
G(s)=C(sI A) 1B=(001) 2s+30
1 1s 3
www.
0 s 1
1
G(s)=C(sI A)B=(111) 0s 1
31s+2
s2+2s+1s+21 10
12
(111) 3 =3s+2ss 01
s+2s+s+3 2 33sss 11
1
=32s2 12s2+3s
s+2s+s+3
(
C1sn 1+"+Cn 1s+Cn
8. 解：G(s)=n+C0. n 1
s+a1s+"+an 1s+an
9. 证明类似定理1.4, 此处略.
aw.
网
1
案
0 1 1
, C=(111).
1
10
01 11
)
com
0 1 2