详细的《数值分析简明教程》第二版课后习题答案
【解】欧先写出高斯-赛德尔迭代:
3(k) ~(k 1)
x x2 4 1
4
3~(k)1(k)9(k)1(k) ~(k 1)
x x x 5 x2 x3 2 213
44164
9(k)1(k)5 ~(k 1)1~(k)
x x 3 x2 x3 2 3
464162
引入松弛因子,得
(1)
1(k)5~(k 1) (k 1)(k)(k 1)~x (1 )x x x1 x1
11 1
44
1(k)5~(k 1) (k 1)(k)
(1 )x2 ~x2(k 1) x2 x2 x2
44
1(k)5~(k 1) (k 1)(k)(k 1)~x (1 )x x x3 x3
3 33
44
将方程组(1)代入(2),并化简
(2)
1(k)15(k) (k 1)
x x1 x2 5 1
416
(k 1)29(k)5(k)5
x2 x3 x2
64162
45(k)11(k)25 (k 1)
x x2 x3 3
256648
(3)